- #打卡
- #打卡组队
Swift刷题打卡,不能再颓了

83213
// 102. Binary Tree Level Order Traversal
// 3
// / \
// 9 20
// / \
// 15 7
func leverOrder(_ root: TreeNode?) -> [[Int]] {
var result = [[Int]]()
guard let root = root else {
return result
}
var queue = [TreeNode]()
queue.append(root)
while !queue.isEmpty {
let size = queue.count
var arr = [Int]()
for _ in 0..<size {
let cur = queue.removeFirst()
arr.append(cur.val)
if let left = cur.left {
queue.append(left)
}
if let right = cur.right {
queue.append(right)
}
}
result.append(arr)
}
return result
}
var n1 = TreeNode(3)
var n2 = TreeNode(9)
var n3 = TreeNode(20)
var n4 = TreeNode(15)
var n5 = TreeNode(17)
n1.left = n2
n1.right = n3
n3.left = n4
n3.right = n5
let ans = leverOrder(n1)
print(ans)
// 3
// / \
// 9 20
// / \
// 15 7
func leverOrder(_ root: TreeNode?) -> [[Int]] {
var result = [[Int]]()
guard let root = root else {
return result
}
var queue = [TreeNode]()
queue.append(root)
while !queue.isEmpty {
let size = queue.count
var arr = [Int]()
for _ in 0..<size {
let cur = queue.removeFirst()
arr.append(cur.val)
if let left = cur.left {
queue.append(left)
}
if let right = cur.right {
queue.append(right)
}
}
result.append(arr)
}
return result
}
var n1 = TreeNode(3)
var n2 = TreeNode(9)
var n3 = TreeNode(20)
var n4 = TreeNode(15)
var n5 = TreeNode(17)
n1.left = n2
n1.right = n3
n3.left = n4
n3.right = n5
let ans = leverOrder(n1)
print(ans)